Question from very important topics are covered by NCERT Exemplar Class 9.. You also get idea about the type of questions and method to answer in your Class 9th examination. Answer: Galileo Galilei and Isaac Newton. 1. The total displacement of each car can be obtained by calculating the area beneath the speed-time graph. A farmer moves along the boundary of a square field of side 10m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position? It is a detailed and well-structured solution for a solid grip of the concept-based learning experience. What is reproduction? Answer: Reproduction which involves the … Motion Class 9 Extra Questions and Answers Science Chapter 8 In this page, we are providing Motion Class 9 Extra Questions and Answers Science Chapter 8 pdf download. How is our atmosphere different from the atmospheres on Venus and Mars? But OA is the velocity of the object and OC represents time. It is developed keeping in mind the concept-based approach along with the precise answering method for examinations. A trolley, while going down an inclined plane, has an acceleration of 2 cm s-2. In this article, students will learn everything that they need to know for writing. A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h–1 in 10 minutes. 10. A stone is thrown in a vertically upward direction with a velocity of 5 m s-1. The first graph describes uniform motion and the second one describes non-uniform motion. (ii) non-uniform acceleration? NCERT Solutions for Class 9 science is the contribution by the faculty having vast teaching experience. What is the average speed for Abdul’s trip? This distance-time graph can be plotted as follows. MCQs from CBSE Class 9 Science Chapter 8: Motion 1. A bus decreases its speed from 80 km h–1 to 60 km h–1 in 5 s. Find the acceleration of the bus. MCQ Questions for Class 8 Science with Answers were prepared based on the latest exam pattern. Refer NCERT Solutions for Class 9 for best scores in board and competitive exams. Therefore the car travels a total of 12 meters in the first four seconds. Define the following terms: (a) Distance (b) Displacement (c) Speed (d) Velocity (e) Acceleration (f) Uniform motion (g) Uniform circular motion (h) Scalar quantity (i) Vector quantity. NCERT Class 9 Science Chapter 8 is covered under Unit III: Motion, Force and Work and can get you maximum marks. Now, the area below the velocity-time graph is the area of the rectangle OABC, which is given by OA*OC. ( ) Each sperm is a single cell. Free Online MCQ Questions for Class 9 Science Chapter 8 – Motion with Answers. Solution. Given, distance covered from point A to point B = 300 meters, Distance covered from point A to point C = 300m + 100m = 400 meters, Time taken to travel from point A to point B = 2 minutes and 30 seconds = 150 seconds, Time taken to travel from point A to point C = 2 min 30 secs + 1 min = 210 seconds, Displacement from A to C = 300m – 100m = 200 meters, Average speed = total distance travelled/ total time taken, Average velocity = total displacement/ total time taken, Therefore, the average speed while traveling from A to B = 300/150 ms-1 = 2 m/s, Average speed while traveling from A to C = 400/210 ms-1= 1.9 m/s, Average velocity while traveling from A to B =300/150 ms-1= 2 m/s, Average velocity while traveling from A to C =200/210 ms-1= 0.95 m/s. Can it have zero displacement? Uniform and non-uniform motions of objects are explained through the graph and examples. But what if you didn’t get NCERT Solutions of chapter 8 science class 9 the first time that you read the chapter? It refers to the distance moved by an object over a time interval. ... NCERT Solutions offer comprehensive answers to all the questions to help students in their preparations. Here we are providing the solutions to all the chapters of NCERT Science Class 9 Textbook for the students. 1. What is the nature of the distance-time graphs for uniform and non-uniform motion of an object? 2. This is the minimum displacement. Students can access the Multiple Choice Type Questions for Class 8 Science helps you to be prepared for the exam. Refer NCERT Solutions for Class 9 for best scores in board and competitive exams. Question 10. Which of the following is true for displacement? Therefore, total distance traveled by B when it crosses C = 9*(4/7) = 5.14 km. It refers to the displacement of a given object over a time interval. What does the path of an object look like when it is in uniform motion? Check the below NCERT MCQ Questions for Class 9 Science Chapter 8 Motion with Answers Pdf free download. Since a = 0.1 m.s-2, v = 12 m.s-1, u = 0 m.s-1, and t = 120s, the following value for s (distance) can be obtained. Provides completely solved solutions to all the questions present in the respective NCERT textbooks. Required fields are marked *. (c) It is possible; for an object accelerating in a circular trajectory, the acceleration is perpendicular to the direction followed by the object. Distance-time graph and velocity-time graph, which are considered as the important concepts for examination are explained in an easy way in NCERT Solutions. Students can download NCERT class 9 science ch 8 solutions from Vedantu for free. Distance covered in 40 seconds = 200π meters, Distance covered in 2minutes and 20 seconds (140 seconds) = 140 * 200π/40 meters, = (140*200*22)/(40* 7) meters = 2200 meters, Number of laps completed by the athlete in 140 seconds = 140/40 = 3.5. Can it have zero displacement? (a) It is possible; an object thrown up into the air has a constant acceleration due to gravity acting on it. Chapter 8: Motion. On his return trip along the same route, there is less traffic and the average speed is 30 km.h–1. Therefore, the net displacement will be equal to the diameter of the track, which is 200m. Considering an object in uniform motion, its velocity-time graph can be represented as follows. For any error, please give your feedback, so that we can modify the contents. What is the quantity which is measured by the area occupied below the velocity-time graph? Your email address will not be published. Those students who refer the NCERT Solutions regularly are benefited with the comprehensive methodology of the topic, and also with the detailed step by step procedure, which will fetch them good marks in their examinations. (b) In uniform motion. Check the below NCERT MCQ Questions for Class 9 Science Chapter 8 Motion with Answers Pdf free download. (a) Given, the bust starts from rest. Yes, an object moving a certain distance can have zero total displacement. Page No: 100. Therefore, the ball reaches the ground after 2 seconds. Therefore, the stone reaches a maximum height of 1.25 meters in a timeframe of 0.5 seconds. Statement (a) is false because the displacement of an object which travels a certain distance and comes back to its initial position is zero. Abdul, while driving to school, computes the average speed for his trip to be 20 km.h–1. Answer: A pair of testes, two spermducts and a penis. Since there is no change in the velocity of the object (Y-Axis value) at any point of time (X-axis value), the object is said to be in uniform motion. 7. A train starts from rest and accelerate uniformly at the rate of 5 m/s2for 5 sec. Under what condition(s) is the magnitude of average velocity of an object equal to its average speed? (b) it is impossible; acceleration implies an increase or decrease in speed, and uniform speed implies that the speed does not change over time. (b) Which part of the graph represents uniform motion of the car? (a) since the slope of line B is the greatest, B is traveling at the fastest speed. Students often face challenges in answering those questions. The nucleons are (a) protons and electrons (b) neutrons and electrons (c) protons and neutrons (d) none of these 2. 1. NCERT Solutions for Class 9 Science Chapter 8 Motion is designed with the intention of clarifying doubts and concepts easily. 3. The phenomenon of motion was placed on a sound scientific footing by two scientists. NCERT Solutions for Class 9th Science Chapter 8 : Motion. State which of the following situations are possible and give an example for each of these: (a) an object with a constant acceleration but with zero velocity (b) an object moving with an acceleration but with uniform speed. A driver of a car travelling at 52 km h–1 applies the brakes and accelerates uniformly in the opposite direction. Students can download NCERT class 9 science ch 8 solutions from Vedantu for free. All the questions are provided with correct answers. Therefore, the shaded area can be represented as: Area under the velocity-time graph = velocity*time. After what time will it strike the ground? Have a glance at the MCQ of Chapter 6 Science Class 8 and cross-check your answers during preparation. Choose the correct option: 1. [NCERT] Oviparous animals give birth to young ones. We all often say to a driver that drive carefully or drive slowly. 4. In Text Question. Answer: Reproduction is the biological process by which new individual organisms are produced from their parents. Students can Download Science Chapter 8 Chalane Questions and Answers, Notes Pdf, KSEEB Solutions for Class 9 Science in Kannada helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Answer: (b) Question 3. Question 11. Motion CBSE Class 9 Science Chapter 8 - Complete explanation and Notes of the chapter 'Motion'.. An object has moved through a distance. Ans: Ans: Earth’s atmosphere is composed of various gases like oxygen, carbon dioxide, nitrogen, water vapour along with various gases in small quantities, hence making it a balanced composition which is livable than other planets. NCERT Solutions for Class 9 Science Chapter 8 : Motion – All Questions. A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 m s-2, with what velocity will it strike the ground? Here you can get NCERT Extra Questions for Class 9 Science with Answers. NCERT for Class 9 Science Solutions are made available in both web and PDF format for ease of access. If that is the case, then you are in the right place. 1. 9. Find its acceleration. Find the time taken by the body to move through a distance of 12 m. 4.0.2 A truck of mass … Given, the initial velocity (u) = 80km/hour = 80000m/3600s= 22.22 m.s-1, The final velocity (v) = 60km/hour = 60000m/3600s= 16.66 m.s-1, Therefore, acceleration (a) =(v-u)/t = (16.66 m.s-1 – 22.22 m.s-1)/5s. Page No: 100. Question 1. I am so HELPFUL from this site for my exams as my exam are coming. 3. Uniform circular motion concept is made understandable in a simple way. Students must solve the NCERT questions regularly to score well in their class 8th examination. (c) since there are 7 unit areas of the graph between 0 and 4 on the Y axis, 1 graph unit equals 4/7 km. What does the odometer of an automobile measure? It can be calculated as: (1/2)*4*6 = 12 meters. 1.2 Class 7 Geography Chapter 8 Human Environment Interactions the Tropical and the subtropical Region Exercise Questions and Answers Our team of subject expert teachers has prepared and reviewed the NCERT Solutions for Class 7 Social Science Geography Chapter 8 Human Environment Interactions the Tropical and the subtropical Region are given here will help you to prepare well and score good … 4. An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 minutes 20 s? (b) Its magnitude is greater than the distance travelled by the object. approaches students in a student-friendly way and is loaded with questions, activities, and exercises that are board and competitive exam-oriented. What can you say about the motion of an object whose distance-time graph is a straight line parallel to the time axis? Therefore, the first car (which was traveling at 52 kmph) traveled farther post the application of brakes. It is a detailed and well-structured solution for a solid grip of the concept-based learning experience. Chapter 9: Force and Laws of Motion Therefore, initial velocity (u) = 0 m/s, Acceleration is given by the equation a=(v-u)/t, Therefore, terminal velocity (v) = (at)+u. (b) … An object has moved through a distance. 2. Calculate its speed if it takes 24 hours to revolve around the earth. It also has Exemplar problems, Questions from Previous year question papers, CBSE sample papers, Worksheets, Extra questions, tips and tricks. Since the initial point of object C is 4 graph units away from the origin, Its initial distance from the origin is 4*(4/7)km = 16/7 km, When A passes B, the distance between the origin and C is 8km, Therefore, total distance traveled by C in this time = 8 – (16/7) km = 5.71 km. 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